Answer by Bilal for Deinit UIImpactFeedbackGenerator
You are creating a new UIImpactFeedbackGenerator every time generateHapticFeedback method is called. So even if you set feedbackGenerator to nil, a new object will be created at this line...
View ArticleDeinit UIImpactFeedbackGenerator
I init a UIImpactFeedbackGenerator with a timer with TimeInterval=1.0. After some seconds, I call the deinitHapticFeedback(), as described below and navigate to the next view controller, but the...
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